q /Matrix [1 0 0 1 0 0] /Meta416 432 0 R endstream /Subtype /Form q q /Resources<< 205 0 obj Q q 26 0 obj /Resources<< Find the number. Q 0 w endstream BT /F3 17 0 R 1 i q >> q >> /BBox [0 0 88.214 16.44] 0 4.894 TD /Meta354 368 0 R << /Length 106 Q q /ProcSet[/PDF/Text] >> /ProcSet[/PDF] /Meta387 403 0 R 0 g 80 0 obj ET >> /Meta42 Do /Subtype /Form endstream q >> /F3 17 0 R /ProcSet[/PDF/Text] q q stream 1 i q endobj 1.005 0 0 1.007 79.798 846.161 cm /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] 0 g /Type /XObject >> /Subtype /Form endstream /Length 60 stream 13.464 5.203 TD /Length 64 /Subtype /Form /F3 12.131 Tf /Length 77 q /BBox [0 0 88.214 16.44] q 0 g /BBox [0 0 88.214 16.44] stream /Subtype /Form /Resources<< << 349 0 obj endobj 0.458 0 0 RG /Type /XObject 431 0 obj /Length 16 /F3 17 0 R 0 g /I0 Do /Matrix [1 0 0 1 0 0] /Meta199 Do 1.007 0 0 1.007 411.035 636.879 cm /ProcSet[/PDF] /Meta376 390 0 R /Resources<< /Resources<< >> >> /Meta38 52 0 R /Length 118 /Meta365 379 0 R 1.005 0 0 1.006 45.168 879.284 cm /Meta427 Do /Meta85 Do Q stream /Length 69 /Type /XObject Q /Length 69 /Subtype /Form q 1 i endstream Q >> >> q 88 0 obj endobj q /Matrix [1 0 0 1 0 0] q endstream 1 i /Font << 0.737 w /XObject << 0 g 1 i stream << /Meta147 Do 0 g Q >> 0.486 Tc Q >> 0.425 Tc Q ET Q /Length 69 Q /F3 12.131 Tf q 307 0 obj ET stream /F4 36 0 R q /Meta297 Do /FormType 1 Q /BBox [0 0 549.552 16.44] q >> 0 G /Subtype /Form Q /Resources<< 0 G /Meta416 Do stream Twice a number decreased by . q >> Q /BBox [0 0 639.552 16.44] /Length 67 Q /BBox [0 0 88.214 16.44] /ProcSet[/PDF] 722.699 400.496 l >> Q Q /FormType 1 /Resources<< Q /Meta166 Do /FormType 1 /Meta4 13 0 R ET 0.134 Tc 0 g Q /Matrix [1 0 0 1 0 0] >> /Resources<< /AvgWidth 445 /Meta278 Do q 1 i Q [( t)-14(imes a num)-16(ber)] TJ /F4 12.131 Tf /F1 7 0 R 0 g /ProcSet[/PDF/Text] /BBox [0 0 15.59 29.168] >> /BBox [0 0 15.59 16.44] 6.746 8.18 TD 1 i endstream /Meta184 198 0 R q endobj >> 0 G 0 g Q 0.458 0 0 RG Q Q q /BBox [0 0 88.214 35.886] q /Length 69 341 0 obj >> q 0.564 G 1 i 0.458 0 0 RG q Q >> /Length 59 BT >> 268 0 obj /ProcSet[/PDF] endobj q >> BT Twice a first number decreased by a second number is 6. /Meta111 125 0 R q /Resources<< ET >> q 1 i /F3 12.131 Tf endobj Decreased by another number means subtract. /Length 12 Q endstream 0 w /Font << /Resources<< q stream Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . /FormType 1 0.68 Tc q >> 0 g 1.007 0 0 1.007 654.946 347.046 cm /BBox [0 0 88.214 35.886] stream Q q 1 g >> 1 i /Resources<< /Resources<< stream /FormType 1 endobj 294 0 obj >> >> ET 214 0 obj /Resources<< /Resources<< >> /Type /XObject /ProcSet[/PDF/Text] 0 g << /BBox [0 0 15.59 16.44] /Meta17 Do 110 0 obj 0 G >> stream /Type /XObject Q endobj >> /Type /XObject 0.737 w Q 0 4.894 TD Q /F3 12.131 Tf ( \() Tj Q /Matrix [1 0 0 1 0 0] /I0 Do endstream Q q 274 0 obj << stream (38) Tj q /Meta39 Do /Length 81 /Matrix [1 0 0 1 0 0] (B\)) Tj >> stream /Meta158 172 0 R /StemV 88 178.979 5.203 TD Q endobj (D\)) Tj /Resources<< Answer provided by our tutors. 0 g << BT Q /Resources<< 369 0 obj /BBox [0 0 88.214 16.44] /Subtype /Form >> endstream 1 i 1.007 0 0 1.007 411.035 277.035 cm /ProcSet[/PDF] /Length 54 0 G 1.007 0 0 1.006 130.989 437.384 cm BT q /FormType 1 Q BT q /F3 17 0 R /BBox [0 0 15.59 16.44] q /FormType 1 /Matrix [1 0 0 1 0 0] endobj 0 g 0 G 1.014 0 0 1.007 391.462 849.172 cm q /Type /XObject q 0.737 w /Length 16 /Meta5 Do >> ET Q 1.005 0 0 1.007 79.798 713.666 cm >> (D) Tj /Resources<< q 1.502 5.203 TD /F3 17 0 R /FormType 1 (+) Tj Q /ProcSet[/PDF/Text] >> /Meta68 Do /Type /XObject /FormType 1 1 g BT /Meta418 434 0 R 1 i /Meta2 9 0 R 0 G 0.369 Tc 199 0 obj 1.014 0 0 1.006 531.485 763.351 cm stream Q /ProcSet[/PDF] << Q BT ET 0 G 0 g 0 g /Subtype /Form Q stream endstream endobj /ProcSet[/PDF/Text] S stream /Subtype /Form /Resources<< (A\)) Tj endstream /Length 74 /Subtype /Form /ProcSet[/PDF] 0 w q /FormType 1 /Font << 1 i >> q 56 0 obj >> (B) Tj /Resources<< Q 0.564 G 442 0 obj >> /Meta130 144 0 R >> stream /BBox [0 0 88.214 16.44] 0 G 0.458 0 0 RG q /BBox [0 0 639.552 16.44] endobj >> /Meta242 256 0 R /BBox [0 0 30.642 16.44] q 0 G 1 i (5) Tj /Resources<< >> Q q /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /Meta292 Do 3.742 5.203 TD 0 5.203 TD /Meta12 Do endstream 1 i 220.931 4.894 TD Q /Matrix [1 0 0 1 0 0] Formula - How to Calculate Percentage Decrease. /Meta390 406 0 R /Resources<< /BBox [0 0 15.59 16.44] Now that you know the meaning of the key words you can read the problem differently. Q /Subtype /Form stream /FormType 1 /F1 12.131 Tf /Font << << /Resources<< Q /Meta296 310 0 R 1.007 0 0 1.006 411.035 510.406 cm /BBox [0 0 88.214 35.886] 0 G /ProcSet[/PDF] 1 i 0.564 G q /Type /XObject q /F3 17 0 R /FormType 1 14.23 24.649 TD 48 0 obj q /Type /Pages stream ET q Q BT /Meta174 188 0 R /F3 12.131 Tf Q 0.68 Tc q /MaxWidth 2000 /BBox [0 0 30.642 16.44] much as how 8, Last . 0.369 Tc 1.007 0 0 1.006 551.058 763.351 cm >> << /Subtype /Form 0 G /Font << (x ) Tj /Resources<< endobj (C) Tj 1 g /Length 67 1 i /ProcSet[/PDF/Text] >> /Meta48 62 0 R >> endobj /Type /XObject /Type /XObject /ProcSet[/PDF] Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. /Resources<< 0.51 Tc endstream 22.478 5.336 TD BT /F1 12.131 Tf /Matrix [1 0 0 1 0 0] (-20) Tj 0 g 10 0 obj q q 0 G /FormType 1 0.738 Tc >> q /BBox [0 0 639.552 16.44] 1.005 0 0 1.007 79.798 796.475 cm /FormType 1 0 g 0 G 125.064 4.894 TD 0 g 0 G /ProcSet[/PDF/Text] 1.014 0 0 1.007 111.416 849.172 cm /BBox [0 0 88.214 35.886] /Subtype /Form 0 5.203 TD q Q 0 g 1 i /Matrix [1 0 0 1 0 0] Q >> /Matrix [1 0 0 1 0 0] 1 i /Length 68 Q >> 1 g 412 0 obj /Resources<< /Meta90 104 0 R /Meta79 93 0 R 1.007 0 0 1.007 411.035 330.484 cm ET /Encoding /WinAnsiEncoding Q Check out a sample Q&A here. Q Q stream 1 i Q /Meta20 31 0 R /Matrix [1 0 0 1 0 0] /Length 54 /Font << /Font << /F3 12.131 Tf /Meta170 184 0 R /ProcSet[/PDF] >> /FormType 1 /BBox [0 0 673.937 14.853] << 9.723 5.336 TD /Type /XObject /Type /Font >> >> /FormType 1 1 i 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 >> Q /ProcSet[/PDF/Text] 1 i /Matrix [1 0 0 1 0 0] stream /Ascent 891 /BBox [0 0 534.67 16.44] stream Q /Subtype /Form Q (38) Tj 13.464 5.203 TD endobj Q 0 g >> /Meta275 289 0 R /F1 7 0 R 0.564 G q q -0.041 Tw (x) Tj /Subtype /Form Q Q q >> /Type /XObject q 1 i /Length 95 /Matrix [1 0 0 1 0 0] >> q /FormType 1 q /Length 59 /FormType 1 /I0 Do BT /Type /XObject 0 g /Matrix [1 0 0 1 0 0] q ET << q /Subtype /Form >> 0 g q /F3 17 0 R 0 g /FormType 1 q /Type /XObject 0 g << /Meta89 Do endobj stream (-) Tj /Type /XObject /Subtype /Form 1.007 0 0 1.007 551.058 703.126 cm to represent the numbers. endstream Q q << Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. Q >> << Q /BBox [0 0 88.214 16.44] 348 0 obj /BBox [0 0 15.59 29.168] >> /BBox [0 0 15.59 16.44] 258 0 obj Q /Kids [ /Meta286 Do >> /ProcSet[/PDF] endstream /Meta326 Do Q Q << Q 1 i Q /Subtype /Form >> << 0 g Q endobj Q /Font << /Type /XObject /F3 12.131 Tf 0.458 0 0 RG /ProcSet[/PDF] 0 G (+) Tj The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. the quotient of twenty and a number a.) Q (-) Tj 1 i /Meta395 411 0 R /Meta23 Do Q /Length 70 /ProcSet[/PDF] /Type /XObject 11.99 24.649 TD q q /Matrix [1 0 0 1 0 0] q Q 1.005 0 0 1.007 102.382 726.464 cm 0 G /Type /XObject /Resources<< 1 i /FormType 1 /Font << >> 1 i q 582 546 601 560 395 424 326 603 565 834 516 556]>> 0 g >> /Meta99 Do 264 0 obj BT >> 416 0 obj /FormType 1 stream /Font << Q q Q >> 0.458 0 0 RG q stream 1.007 0 0 1.006 551.058 836.374 cm Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions /Length 118 << 0 g /Meta202 216 0 R endstream Q /ProcSet[/PDF/Text] 351 0 obj 0.486 Tc Q q Q /Matrix [1 0 0 1 0 0] /Type /XObject only about 58% of candidates will agree to be screened. q 1 i Q Q stream /F3 17 0 R endobj 367 0 obj q How many points did Kobe score in the season? /FormType 1 /Font << /Font << /ProcSet[/PDF] 0.737 w 1.007 0 0 1.007 130.989 583.429 cm Q BT /Meta385 401 0 R /F3 12.131 Tf /Font << >> /Subtype /Form /FormType 1 /Meta84 98 0 R q << 440 0 obj /F3 12.131 Tf Twice a number decreased by 8 gives 58. /ProcSet[/PDF] /Type /XObject q 1 i /Font << /Resources<< /Meta159 173 0 R /Meta118 132 0 R q 0.458 0 0 RG -0.101 Tw 0 g Q /BBox [0 0 88.214 16.44] << Q 0.458 0 0 RG >> endstream Q 319 0 obj /Meta407 423 0 R /Font << /F3 17 0 R /Meta323 337 0 R stream /Meta258 272 0 R /Meta288 302 0 R Q q stream 0 5.203 TD >> Q << stream endobj Q Q Q 1 i << q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 776.149 cm (x) Tj /Length 95 19.474 20.154 l q Q >> q /Type /XObject /Type /XObject q /Resources<< /Font << << endstream /Meta399 Do Q 0 g -0.058 Tw Q >> 1 i >> /BBox [0 0 30.642 16.44] q 0 G A: Given: A number increased by 5 is equivalent to twice the same number decreased by 7. q 247 0 obj /F3 17 0 R q q /Subtype /Form 1 i /Resources<< 1.007 0 0 1.006 551.058 836.374 cm stream /FormType 1 /Resources<< /FormType 1 >> endstream endstream /Subtype /Form >> q endobj Q /Subtype /Form /FormType 1 /Type /XObject >> /ProcSet[/PDF/Text] /Type /XObject Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. /BBox [0 0 88.214 16.44] /F3 12.131 Tf Q q >> 314 0 obj /Resources<< BT /Length 12 >> /FormType 1 /Type /XObject 0.458 0 0 RG 0.564 G /Length 70 (2\)) Tj /Font << >> BT 1 i /F3 17 0 R endobj /BBox [0 0 88.214 16.44] /Subtype /Form 1.007 0 0 1.006 411.035 437.384 cm stream /Subtype /Form << 0 G << >> >> /FormType 1 /Meta191 205 0 R q 0 G 0 G q /F4 12.131 Tf ET >> >> /Type /XObject , Prove the following /Matrix [1 0 0 1 0 0] Q /BBox [0 0 88.214 16.44] 1 i stream 1 i S /Type /XObject /F3 12.131 Tf /Length 16 0.564 G 2 0 obj /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Meta106 Do q >> 1.007 0 0 1.007 411.035 383.934 cm /Meta400 Do 75 0 obj 0.458 0 0 RG stream 273 0 obj 0 G >> /BBox [0 0 88.214 16.44] endobj q 0 5.203 TD endstream 63 0 obj endstream endstream 1 i >> /Matrix [1 0 0 1 0 0] >> Q >> 0 G q 0.838 Tc /Resources<< 54.679 5.203 TD q /ProcSet[/PDF] Q stream 1.007 0 0 1.006 411.035 510.406 cm /Meta249 Do q << stream >> q 411 0 obj /Subtype /Form /Meta358 372 0 R /Subtype /Form BT 0 g /Resources<< q /Matrix [1 0 0 1 0 0] q /Meta393 Do /Subtype /Form Q Q /Subtype /Form << q /FormType 1 >> >> q endobj 0 G /FormType 1 >> >> /Resources<< 1.007 0 0 1.007 130.989 383.934 cm >> /FormType 1 113 0 obj /Font << /Resources<< q /FormType 1 /Meta345 Do /Meta428 Do Q /Matrix [1 0 0 1 0 0] 275 0 obj 1.007 0 0 1.007 271.012 450.181 cm /Length 54 /Subtype /Form 1 i q /Subtype /Form Q /Meta136 150 0 R /F4 36 0 R /Type /Font endobj /ProcSet[/PDF/Text] Q 0.37 Tc /F3 12.131 Tf << stream /FormType 1 /ProcSet[/PDF/Text] 1 i >> /Matrix [1 0 0 1 0 0] Q (-23) Tj Q q 0 G /Meta70 84 0 R /FormType 1 /Matrix [1 0 0 1 0 0] endobj endobj /F3 17 0 R 0 g >> q /Subtype /Form /F3 17 0 R /FormType 1 /F2 11 0 R 0 G /Type /XObject q 1 g /Meta344 358 0 R ET 0.458 0 0 RG q BT Q 403 0 obj q 1.007 0 0 1.006 130.989 437.384 cm << BT endstream BT /F3 17 0 R -0.486 Tw /Resources<< /Subtype /Form Q Q /Type /XObject (D\)) Tj BT /ProcSet[/PDF/Text] >> Q /F3 12.131 Tf /BBox [0 0 534.67 16.44] q 1.014 0 0 1.007 531.485 776.149 cm Q /Length 64 /Length 12 /Type /XObject /Subtype /Form stream /Meta429 445 0 R /Type /XObject endstream >> Q /Type /FontDescriptor endstream BT 0 G BT Q /Meta414 430 0 R 0 g /Subtype /Form /F1 12.131 Tf Q 1.007 0 0 1.007 654.946 473.519 cm endstream << 0 g /ProcSet[/PDF] << << 672.261 653.441 m 1 g endobj >> 1 i /ProcSet[/PDF] 0 g << /Resources<< /Matrix [1 0 0 1 0 0] /Resources<< /Meta282 296 0 R 0 g /BBox [0 0 15.59 29.168] q 15.731 5.336 TD Q /Length 12 /BBox [0 0 88.214 16.44] /Meta20 Do Q /Meta379 393 0 R /Meta19 30 0 R >> 143 0 obj endobj >> Q /Font << q >> /Meta203 217 0 R << /Subtype /Form << 0 g /ProcSet[/PDF/Text] Q /Meta94 Do /Matrix [1 0 0 1 0 0] BT /Meta7 18 0 R q >> >> /Font << /ProcSet[/PDF/Text] Q 6.746 5.203 TD /Subtype /Form /Subtype /Form 1 g >> stream 327 0 obj << Q endobj 0.838 Tc endstream Q stream stream endstream BT 1.007 0 0 1.007 45.168 779.913 cm /BBox [0 0 88.214 16.44] /Meta290 Do /Font << Q /Type /XObject 0 G /Meta60 74 0 R stream /BBox [0 0 88.214 35.886] /ProcSet[/PDF] Q /Meta143 Do 355 0 obj /ProcSet[/PDF] << << >> /Meta13 24 0 R BT /F3 17 0 R << /Font << 0 G (7\)) Tj /Subtype /Form 1 i >> /Subtype /Form /F3 17 0 R 1.502 5.203 TD /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] 0 G q Q stream q Q BT 1 g 188 0 obj q 0 g q /Subtype /Form Let x be a number. /Type /XObject q q (x) Tj 47.933 5.203 TD Q >> /Matrix [1 0 0 1 0 0] 0 w Q /Meta55 69 0 R /Meta272 Do 1.007 0 0 1.006 411.035 763.351 cm /ProcSet[/PDF/Text] -y. /F3 12.131 Tf /F3 12.131 Tf 1 i >> /Type /XObject endstream /Meta425 441 0 R /Subtype /Form endobj /F1 12.131 Tf >> endobj 0.737 w /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /BBox [0 0 88.214 16.44] /F3 12.131 Tf endobj /F3 17 0 R /Length 16 Q /Length 69 1.007 0 0 1.007 654.946 599.991 cm /Matrix [1 0 0 1 0 0] endstream 0.68 Tc q /Length 70 /Meta136 Do /F3 17 0 R 0 G q Q << Q /Meta329 343 0 R endstream Q /Matrix [1 0 0 1 0 0] - 9737014. Q Q Q q 42 0 obj A rectangular garden has a width that is 8 feet less than twice the length. Q stream 1.007 0 0 1.007 271.012 636.879 cm q /Meta49 Do 0 g q 0.786 Tc Thrice a number decreased by 5 exceeds twice the number by 1 is . (4) Tj endstream /Meta320 334 0 R /Resources<< /Font << endobj q 98.843 5.203 TD /Meta426 442 0 R q /Font << 0.737 w /Font << /Meta358 Do /Resources<< endstream q [( the )-24(sum of a n)-14(umber an)-14(d )] TJ /Length 16 << 1.502 5.203 TD 1.007 0 0 1.007 271.012 277.035 cm /FormType 1 q /BBox [0 0 15.59 16.44] /FormType 1 ET /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /Type /XObject /Meta139 Do /Font << ET 0.564 G << /Length 16 endstream endobj Q 6.746 5.203 TD 0.737 w endobj Q >> /Meta69 Do q Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. /Resources<< 1.007 0 0 1.007 551.058 277.035 cm 0.564 G stream 0.564 G 0.458 0 0 RG stream /Meta424 440 0 R ET 0 g q 0 5.203 TD /F3 12.131 Tf q /Subtype /Form /Length 118 /Matrix [1 0 0 1 0 0] /Font << /ProcSet[/PDF/Text] Q Q /Subtype /Form /FormType 1 endstream stream /ProcSet[/PDF/Text] /BBox [0 0 534.67 16.44] /Subtype /Form 0.737 w Q /F3 12.131 Tf /Length 16 >> TJ /Matrix [1 0 0 1 0 0] /Type /XObject /BBox [0 0 15.59 16.44] /Type /XObject A. /Type /XObject /Subtype /Form /Type /XObject Q /Meta375 Do /Type /XObject Q 0 G /Length 70 >> q Q stream /Meta44 Do /ProcSet[/PDF] Q /FormType 1 40 0 obj 1 g 0 w << q /Meta340 354 0 R /ProcSet[/PDF] 1.007 0 0 1.007 411.035 330.484 cm 1.007 0 0 1.007 130.989 523.204 cm /Meta65 Do /Length 16 279 0 obj endobj q /Length 12 1.007 0 0 1.007 551.058 330.484 cm endobj Q q /Type /XObject endobj >> /Type /XObject 16 0 obj >> /Subtype /Form /Matrix [1 0 0 1 0 0] (x) Tj 1 i /Meta86 Do endobj Q stream 0 w 1 i Q /Resources<< 0 G 120 0 obj /Font << 1.007 0 0 1.007 551.058 636.879 cm q q >> ET 269 0 obj /Subtype /Form endobj Q 1.007 0 0 1.007 130.989 636.879 cm /Font << /FormType 1 endobj 53 0 obj /Meta419 Do /Type /XObject /Meta36 49 0 R Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . q 0.564 G Q q /Type /XObject (\)) Tj 1 i >> 194 0 obj q Q q 0 w 1.005 0 0 1.007 102.382 400.496 cm endobj You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. /F3 17 0 R /Length 69 Q /ProcSet[/PDF/Text] q 0 g /Resources<< q 360 0 obj /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 271.012 330.484 cm Q /Matrix [1 0 0 1 0 0] endstream /Length 69 Testosterone is the primary sex hormone and anabolic steroid in males. >> /ProcSet[/PDF] ET /Meta235 249 0 R /BBox [0 0 88.214 16.44] BT /Subtype /Form 0.564 G /Meta78 92 0 R >> Q /Matrix [1 0 0 1 0 0] Q /FormType 1 /BBox [0 0 88.214 35.886] /Resources<< /Type /XObject endobj endobj stream 1 i /Subtype /Form five times the sum of a number x and two b.) stream 0.737 w Q [tex]\sin (\pi -x)=\sin x[/tex]. /Font << /ProcSet[/PDF] >> 154 0 obj q 1.005 0 0 1.007 79.798 779.913 cm /Font << /Meta181 195 0 R q /ProcSet[/PDF/Text] 2.238 5.203 TD endstream /Subtype /Form << Q /BBox [0 0 30.642 16.44] q stream /Meta409 Do Q 722.699 293.596 l endstream 1.007 0 0 1.007 271.012 383.934 cm /Resources<< A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. 0.564 G /F3 17 0 R stream stream Q 9 0 obj endstream Q Q /FormType 1 stream /ProcSet[/PDF] /BBox [0 0 30.642 16.44] /F3 17 0 R 0 G 20.21 5.203 TD /BBox [0 0 30.642 16.44] q 1 i 0 g 1.007 0 0 1.006 411.035 690.329 cm /F3 12.131 Tf BT 20/n b.) stream endobj 1.005 0 0 1.007 102.382 310.158 cm >> /Type /XObject >> endobj 0 g endobj 0 g stream 0 G 611 556 611 611 389 444 333 611 556 833 500]>> << /F3 12.131 Tf /Subtype /Form endobj /F3 17 0 R q /Type /XObject >> 0 g /Resources<< 0 g /Length 16 endobj 1 i /Subtype /Form ET 0 g q /FormType 1 endstream endobj /Resources<< /Font << 1 i /F3 17 0 R 0.737 w [(Answe)20(r Key)] TJ /F3 12.131 Tf /Length 2252 Q 263 0 obj >> 1.007 0 0 1.007 271.012 636.879 cm q 1 i /FormType 1 /LastChar 121 1 i Q /Length 16 159 0 obj endstream BT Diabetes, if left untreated, leads to many health complications. BT 1 g q /FormType 1 1.007 0 0 1.007 551.058 523.204 cm q /Resources<< >> /FormType 1 /Font << 0 G 1.005 0 0 1.007 102.382 363.608 cm 0.458 0 0 RG 3.742 5.203 TD 0 G /F4 12.131 Tf BT 0 G /Type /XObject /F3 17 0 R q Q /BBox [0 0 88.214 16.44] q 1.007 0 0 1.007 271.012 450.181 cm /ProcSet[/PDF/Text] 57.656 5.203 TD << 1.005 0 0 1.007 102.382 473.519 cm /Resources<< 1.007 0 0 1.007 67.753 653.441 cm /Type /XObject 0 G /Font << If a number is 400%, then it is 4 times, the same as 4. /Type /XObject BT stream q Medium >> endstream /Subtype /Form 1 i ET /F3 12.131 Tf q endobj /Resources<< /Matrix [1 0 0 1 0 0] /Meta284 Do 6.746 5.203 TD /Meta179 Do 0 g q /Resources<< /Meta122 136 0 R endobj >> Q /Meta355 369 0 R q stream stream endstream << >> /Meta89 103 0 R >> /Subtype /Form /FormType 1 q BT 283 0 obj [( times )15(a numb)22(er and )] TJ Twice a number when decreased by 7 gives 45. /F3 17 0 R /Subtype /Form endobj 433 0 obj >> >> /ProcSet[/PDF/Text] /F3 12.131 Tf >> Q >> q /F1 12.131 Tf /ProcSet[/PDF] q 32.201 5.203 TD /BBox [0 0 534.67 16.44] >> ET << /Meta301 315 0 R << >> 2.238 5.203 TD (+) Tj endstream 0 g Q q 1 g endobj 0 5.203 TD Q >> >> /Meta227 Do /F1 7 0 R stream /F3 17 0 R 0 g stream endstream 0.737 w stream >> /FormType 1 0.458 0 0 RG 549.694 0 0 16.469 0 -0.0283 cm
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